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Vypo�t�t� limitu:

$$\lim\limits_{x \to 0} {e^{ax}-e^{bx} \over x}$$

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K v�po�tu pou�ijeme vzorec $\lim\limits_{x \to 0} {e^x - 1 \over x} = 1$ a v�tu o limit� slo�en� funkce. Dostaneme:

$$\lim\limits_{x \to 0} {e^{ax}-e^{bx} \over x} = \lim\limits_{x \to 0} \left[ e^{bx} {{e^{(a-b)x}-1} \over (a-b)x} (a-b)\right] = a - b$$


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