Urèete derivaci funkce:
   $$
      y=(5+2x)^{10}(3-4x)^{20}.
   $$
   \reseni
   \begin{equation*}\begin{split}
      y'(x) &=\bigl({(5+2x)}^{10}{(3-4x)}^{20}\bigr)'=      \\
            &={(5+2x)}^{10} {\bigl( {(3-4x)}^{20} \bigr)}' +
              {(3-4x)}^{20} {\bigl( {(5+2x)}^{10} \bigr)}' =\\
            &={(5+2x)}^{10} \cdot (-4) \cdot 20 \cdot {(3-4x)}^{19} +
              {(3-4x)}^{20} \cdot 2    \cdot 10 \cdot {(5+2x)}^9=\\
            &=20{(3-4x)}^{20}{(2x+5)}^9 -
              80{(2x+5)}^{10}{(3-4x)}^{19} =\\
            &=20{(3-4x)}^{19}{(2x+5)}^9\bigl(3-4x - 4(2x+5)\bigr)=\\
            &=20{(4x-3)}^{19}{(2x+5)}^9(12x + 17).
   \end{split}\end{equation*}
